drummyfish/less_retarded_wiki
5
1
Fork 0
Code Issues Pull requests Projects Releases Packages Wiki Activity

Update

Browse source
This commit is contained in:
Miloslav Ciz 2024-05-02 22:35:34 +02:00
parent fab11be42b
commit 1cfa0787d3
16 changed files with 1922 additions and 1760 deletions
Download patch file Download diff file Expand all files Collapse all files

2
exercises.md
View file

@ -228,7 +228,7 @@ Bear in mind the main purpose of this quiz is for you to test your understanding
56. We can rewrite the condition as *f(x + 1) = f(x) + x* from which it's clear that the next number in the sequence is the previous one minus its position (a bit similar to [Fibonacci](fibonacci.md) sequence), so for example this sequence will satisfy the equation: 0, 0, 1, 3, 6, 10, 15, ...
57. [quine](quine.md)
58. swastika
59. Draw any right triangle; drawing an identical triangle mirrored by the hypotenuse clearly makes the both triangles together form a rectangle (it can be shown generally all angles in it will always be 90 degrees) in which the hypotenuse (that the both triangles share) is the rectangle's diagonal. Now draw also the other diagonal of the rectangle. If we draw a circle going through all the rectangle's verticles (which is the same circle that goes through the original triangle's vertices), it is clear (e.g. just by symmteries) its center lies in the middle of the rectangle, i.e. on the intersection of the diagonals; i.e. the circle's center lies in the middle of the hypotenuse, which also implies the hypotenuse is the circle's diameter (it's a straight line going through the circle's center).
59. Draw any right triangle; drawing an identical triangle mirrored by the hypotenuse clearly makes the both triangles together form a rectangle (it can be shown generally all angles in it will always be 90 degrees) in which the hypotenuse (that the both triangles share) is the rectangle's diagonal. Now draw also the other diagonal of the rectangle. If we draw a circle going through all the rectangle's verticles (which is the same circle that goes through the original triangle's vertices), it is clear (e.g. just by symmetries) its center lies in the middle of the rectangle, i.e. on the intersection of the diagonals; i.e. the circle's center lies in the middle of the hypotenuse, which also implies the hypotenuse is the circle's diameter (it's a straight line going through the circle's center).
60. [Deep Blue](deep_blue.md), 1997
61. 436; in the original group each number's digits have a total count of closed loops equal to 2.
62. The most common and natural way is to use a [bit field](bit_field.md), i.e. an "array of bits" -- position of each bit is associated with an object that may potentially be present in the set and the bit's value then says if the object really is present or not. We want to be able to store 32 numbers, so we'll need 32 bits; the lowest bit says if number 1 is present, the next one says if number 2 is present etc. So we can really just use one 32 bit number to store this whole set. Implementing multiset is similar, we just allocate more bits for each potential member to indicate the count; in our case we suppose maximum value 255 so we can use 8 bits for each member (in C we would naturally implement this as an array of bytes), so we'll need 32 * 8 = 256 bits.