Update

exercises.md

@@ -217,7 +217,8 @@ Bear in mind the main purpose of this quiz is for you to test your understanding
 110. A [troll](trolling.md) joins homosexual gayming stream and starts spamming Hitler quotes by which he increases the amount of lulz by X percent. However the gay starts crying so the stream censor quickly bans the poor troll, dropping the lulz to the original level. By how many percent have the lulz decreased now?
 111. What happens in [Forth](forth.md) when you try to define a word with the same name as another already existing word? Will the old word be deleted? Or is this forbidden to do? Also say why.
 112. What's the difference between [lazy](lazy.md) and strict evaluation? Show simple example.
-113. Did you enjoy this quiz?
+113. Write code in [Brainfuck](brainfuck.md) that copies the value in current cell to the cell on to the right, while KEEPING the value in current cell. Of course you may use another temporary cell to do this.
+114. Did you enjoy this quiz?
 
 ### Answers
 
@@ -334,7 +335,8 @@ sin(x) / cos(x) - log2(2) = tg(x) - 1*, so we get *tg(x) >= 1*. So that will hol
 110. If the original level of lulz is *a* and lulz increase is *n*, then *X = 100 * n / a*. The decrease is then *100 * n / (a + n) = 100 * (a * X / 100) / (a + a * X / 100) = X / (1 + X / 100) = 100 * X / (100 + X)*.
 111. It can be done (and it's useful), the new word will shadow the old one -- i.e. invoking the word will execute the latest word of that name -- but the old word will still exist in the dictionary, so that if the new word is deleted the old one becomes accessible again. This is because the dictionary is searched from the newest entries to the oldest (it's usually a linked list starting with the latest defined word).
 112. They're both strategies for evaluating [expressions](expression.md): lazy (also *by need*) evaluates an argument ONLY once it's actually needed, while strict evaluation evaluates all arguments, even if some might not be needed. Example: let's have a function `or3(a,b,c)` which performs logical OR of three values; under strict evaluation all *a*, *b* and *c* will be evaluated and then logical OR will be performed; under lazy evaluation the function may first evaluate one argument, let's say *a*, and if it ends up being TRUE, there is no need to further evaluate *b* and *c* (the result is already known to be TRUE), so they won't be evaluated.
-113. yes
+113. For example `[->+>+<<]>>[-<<+>>]<<`: first we copy the current cell into TWO cells to the right -- one of them is used as a temporary cell; after this we use another loop to copy the value from the temporary cell back to the original location that we zeroes during the first copying.
+114. yes
 
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